Production Rate | 147 | 148 | 149 | 150 | 151 | 152 | 153 |
Probability | 0.05 | 0.10 | 0.15 | 0.20 | 0.30 | 0.15 | 0.05 |
At present the track will hold 150 scooters. Using the following random numbers determine the average number of scooters waiting for shipment in the factory and average number of empty space in the truck. Random Numbers 82, 54, 50, 96, 85, 34, 30, 02, 64, 47.
Solution
Table 2 depicts the production rate and probability.
Production rate | Probability | Cumulative Probability | Random No. Assigned |
147 | 0.05 | 0.05 | 00 – 04 |
148 | 0.10 | 0.15 | 05 – 14 |
149 | 0.15 | 0.30 | 15 – 29 |
150 | 0.20 | 0.50 | 30 – 49 |
151 | 0.30 | 0.80 | 50 – 79 |
152 | 0.15 | 0.95 | 80 – 94 |
153 | 0.05 | 1.00 | 95 – 99 |
Table 3 depicts the simulation worksheet.
Trial No. | Random No. | Simulated Production Rate | Scooter Waiting in the factory | Number of example spaces in the truck |
1 | 82 | 152 | 2 | – |
2 | 54 | 150 | 2 | – |
3 | 50 | 150 | 2 | – |
4 | 96 | 153 | 5 | – |
5 | 85 | 152 | 7 | – |
6 | 34 | 150 | 7 | – |
7 | 30 | 150 | 7 | – |
8 | 02 | 147 | 4 | 3 |
9 | 64 | 151 | 5 | – |
10 | 47 | 150 | 7 | – |
Total | 3 |
Therefore, average number of scooters waiting = 7/10 =0.7/day
Average number of empty space = 3/10 = 0.3/day