operations | M1 | Machines M2 |
M3 | M4 |
O1 | 10 | 15 | 12 | 11 |
O2 | 9 | 10 | 9 | 12 |
O3 | 15 | 16 | 16 | 17 |
Solution:
Introducing a dummy row and applying Hungarian method, you have:
Hungarian method leads to multiple solutions. Selecting (03, M2) arbitrarily.
Therefore, the optimum assignment schedule is O1 to M1, O2 to M3 , O3 to M 2, and O4 to M 4.