## Linear Integrated MCQ Set 1

1. How to obtain a desired amount of multiplication in frequency multiplier?

a) By decreasing the multiplication factor

b) By increasing the input frequency

c) By selecting proper divide by N-network

d) None of the mentioned

### View Answer

_{out}=5×f

_{in}, a divide by N = 5 network is needed.

2. Calculate the output frequency in a frequency multiplier if, f_{in} = 200Hz is applied to a 7 divide by N-network.

a) 1.2kHz

b) 1.6kHz

c) 1.2kHz

d) 1.9kHz

### View Answer

_{out}=divide by N-network x f

_{in}=7x200Hz=1400Hz =>f

_{out}=1.4kHz.

3. For what kind of input signal, the frequency divider can be avoided frequency multiplier?

a) Triangular waveform

b) Square waveform

c) Saw tooth waveform

d) Sine waveform

### View Answer

^{th}harmonic of the input signal without connecting any frequency divider in between the input signal rich in harmonics like square wave.

4. What must the typical value of n for a frequency multiplication / division? (n->order of harmonics)

a) n ≤ 12

b) n > 11

c) n < 10

d) n = 7

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5. Determine the offset frequency of frequency translation, when the output and input frequency are given as 75kHz and 1000Hz.

a) 35 kHz

b) 20 kHz

c) 29 kHz

d) 14 kHz

### View Answer

_{o}= f

_{s}+f

_{1}=> f

_{1}= f

_{o}– f

_{s}= 75kHz-55kHz =20kHz.

6. The frequency corresponding to logic 1 state in FSK is called

a) Space frequency

b) Mark frequency

c) Both mark and space frequency

d) None of the mentioned

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7. Find the frequency shift in FSK generator?

a) 230 Hz

b) 250 Hz

c) 180 Hz

d) 200 Hz

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8. Which filter is chosen to remove the carrier component in the frequency shift keying?

a) Three stage filter

b) Two stage filter

c) Single stage filter

d) All of the mentioned

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## Linear Integrated MCQ Set 2

1. Output current in general purpose op-amp can be increased using

a) Power comparator

b) Power amplifier

c) Power resistor

d) Power booster

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2. Which type of power transistor is chosen for a discrete power booster?

a) Collector follower stage

b) Emitter follower stage

c) Base follower stage

d) None of the mentioned

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3. What is the power dissipation of power transistor?

a) ≅ 0.5W

b) ≤ 0.5W

c) > 0.5W

d) ≠ 0.5W

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4. Burr-Brown 3553 power amplifier is suited for

a) Line driving applications

b) Power supply requirement

c) Bandwidth adjustments

d) High frequency application

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5. Find the IC that can be used for short circuit proof protection?

a) All of the mentioned

b) IC LM384

c) ICL8063

d) ICLM380

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6. Which among the following is ideal for consumer applications?

a) NE5018

b) LM380

c) MC1408

d) SE5018

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7. Bridge power audio amplifier can deliver power upto

a) Twice as much as output of single LM380 amplifier

b) Thrice as much as output of single LM380 amplifier

c) Four times as much as output of single LM380 amplifier

d) Half of the output of single LM380 amplifier

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8.

What precautionary measure should be taken if the circuit is used in a RF-sensitive environment?

a) Connect a parallel combination of RC at the output

b) Connect a series combination of Resistors at the output

c) Connect parallel capacitor at the output

d) Connect a series combination of RC at the output

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9. Which amplifier provides twice output swing as that of LM380 amplifier?

a) Hybrid power amplifier

b) Bridge power audio amplifier

c) Monolithic power audio amplifier

d) Dual power amplifier

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10. A LM380 power amplifier is used in a intercom system with amplifier gain = 50 and the transformer turns ratio is given as 35.Find the overall gain of the circuit.

a) 1880

b) 1750

c) 1370

d) 1580

### View Answer

_{1}/N

_{2}=35; Gain of amplifier = 50.Therefore, the overall gain of the circuit = 50×35 =1750.

11. Determine the work done by the intercom system depending on the position of the switch

a) Remote speaker act as microphone

b) Master speaker act as microphone

c) Remote and master speaker act as microphone

d) None of the mentioned

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## Linear Integrated MCQ Set 3

1. How can a first order low pass filter can be converted into second order low pass filter

a) By adding LC network

b) By adding RC network

c) By adding RC || LC network

d) None of the mentioned

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2. Consider the following specifications and calculate the high cut-off frequency for the circuit given?

a) 95Hz

b) 48Hz

c) 14Hz

d) 33Hz

### View Answer

_{H}= 1/[2 π√(R

_{2}×R

_{3}× C

_{2}× C

_{3})] = 1/[2π√(33kΩ×15kΩ×0.47µF×0.1µF)]= 1/[2π× 4.82×(10

^{-3})]= 33Hz.

3. Find the gain and phase angle of the second order low pass filter?

Where pass band gain of the filter is 5, frequency and the high cut-off frequency of the filter are 3000Hz and 1kHz.

a) None of the mentioned

b) Gain magnitude = -1.03dB , φ =63.32^{o}

c) Gain magnitude = -5.19dB , φ =71.56^{o}

d) Gain magnitude = -4.94dB , φ =90^{o}

### View Answer

_{O}/V

_{in}] =A

_{F}/ √ [1+(f/f

_{h})

^{2}] =5/ √[1+(3000/1000)

^{4}] =5/9.055 =0.55. => [V

_{O}/V

_{in}] = 20log(0.55) =-.519dB. Phase angle of second order low pass filter is given as φ= tan

^{-1}(f/f

_{H}) => φ =71.56

^{o}.

4. Design a second order low pass butterworth filter at a high cut-off frequency of 2.2kHz. Given R_{F}=20kΩ and capacitor 0.047µF.

### View Answer

_{H}=21.2kHz, C

_{2}=C

_{3}=0.047µF R

_{3}= 1/(2πf

_{H}C

_{3}= 1/(2π×2.2kHz×0.047µF) =1/5.9032×10

^{-4}=1.69kΩ. =>R

_{3}=R

_{2}=1.67kΩ Since, R

_{F}=0.586R

_{1}=> R

_{1}=R

_{F}/0.586 =20kΩ/0.586 R

_{1}= 34.13kΩ.

5. A second order low pass filter is given an input frequency of 30kHz and produce a output having phase angle of 79^{o}. Determine the pass band gain of the filter?

a) 11 dB

b) 89.11 dB

c) 46.78 dB

d) None of the mentioned

### View Answer

^{-1}(f/f

_{H}) => f

_{h}=f×tan(φ) =30kHz × tan(79

)= 154.34kHz. Therefore, the pass band gain A

_{F}= f_{H}/0.707 = 154.34kHz/0.707 A_{F}= 218.3 =20log(218.3)= 46.78dB.6. The pass band voltage gain of a second order low pass butterworth filter is

a) 1.586

b) 8.32

c) 0.586

d) 0.707

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7. Arrange the series of step involved in designing a filter for first order low pass filter

Step 1: Select a value of C less than or equal to 1µF

Step 2: Choose a value of high cut-off frequency f_{H}

Step 3: Select a value of R_{1}C and R_{F} depending on the desired pass band gain

Step 4: Calculate the value of R

a) Steps- 2->4->3->1

b) Steps- 4->1->3->2

c) Steps- 2->1->4->3

d) Steps- 1->3->4->2

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8. Frequency scaling is done using

a) Standard capacitor

b) Varying capacitor

c) Standard resistance

d) None of the mentioned

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## Linear Integrated MCQ Set 4

1. Slew rate is defined as the rate of change of

a) Output voltage with respect to time

b) Input voltage with respect to time

c) Both output input voltage with respect to time

d) None of the mentioned

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2. How the slew rate is represented?

a) 1V/ms

b) 1V/s

c) 1V/µs

d) 1mv/S

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3. The natural semiconductor LH0063C has a slew rate of

a) 1400V/µs

b) 6000V/µs

c) 500V/µs

d) None of the mentioned

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4. Rise time is specified for

a) Large signal

b) Medium signal

c) Small signal

d) All of the mentioned

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5. Op-amps with wide bandwidth will have

a) Increase in output

b) Higher slew rate

c) Low response time

d) None of the mentioned

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6. Which factor is responsible for causing slew rate?

a) Internal capacitor

b) External resistor

c) None of the mentioned

d) Both internal and external capacitor

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7. Find the value of capacitor, if the rate of change of voltage across the capacitor is 0.78V/µs and current= 12µA.

a) 5µF

b) 2µF

c) 10µF

d) 15µF

### View Answer

_{c}/dt= I/C => C= I/ (dV

_{c}/ dt) = 12µA/0.78V/µs = 15.38 ≅15µF.

8. Find the slew rate of op-amp from the output waveform given below?

a) 3.4V/µs

b) 10V/µs

c) 20.66V/µs

d) 16V/µs

### View Answer

9. For the circuit shown below, calculate the rate of change of output signal

a) V_{m} ωcosωt

b) V_{m} cosωt

c) V_{m} cosωt/ωt

d) V_{m} cosωt/ω

### View Answer

_{o}= V

_{m}sinωt =>∴ the rate of change of the output voltage = dV

_{o}/dt= d(V

_{m}sinωt)/ dt = V

_{m}ωcosωt.

10. At what condition, the output of op-amp will be free of distortion?

a) Slew rate > 2πfV_{m} /10^{6} V/µs

b) Slew rate > 2πfV_{m} /10^{6} V/µs

c) Slew rate ≥ 2πfV_{m} /10^{6} V/µs

d) Slew rate = 2πfV_{m} /10^{6} V/µs

### View Answer

## Linear Integrated MCQ Set 5

1. How are the square wave output generated in op-amp?

a) Op-amp is forced to operate in the positive saturation region

b) Op-amp is forced to operate in the negative saturation region

c) Op-amp is forced to operate between positive and negative saturation region

d) None of the mentioned

### View Answer

_{sat}and negative saturation, -V

_{sat}.

2. The following circuit represents a square wave generator. Determine its output voltage

a) -13 v

b) +13 v

c) ± 13 v

d) None of the mentioned

### View Answer

_{id}= V

_{in1}– V

_{in2}= 3-7v = -4v. The output of the op-amp in this circuit depends on polarity of differential voltage V

_{0}= -V

_{sat}≅ -V

_{ee}= -13 v.

3. Determine the expression for time period of a square wave generator

a) T= 2RC ln×[( R_{1}+ R_{2}) / ( R_{2})].

b) T= 2RC ln×[( 2R_{1}+ R_{2}) / ( R_{2})].

c) T= 2RC ln×[( R_{1}+ 2R_{2}) / ( R_{2})].

d) T= 2RC ln×[( R_{1}+ R_{2}) / (2 R_{2})].

### View Answer

_{1}+ R

_{2})/( R

_{2})].

4. Determine capacitor voltage waveform for the circuit

### View Answer

_{1}= [(R

_{1}) / (R

_{1}+ R

_{2})] × (-V

_{sat}) = [10kΩ / ( 10 kΩ +11.6 kΩ)] × (-15v) = -7v. Similarly, when the op-amp’s output voltage is at positive saturation, V

_{1}= [(R

_{1}) / (R

_{1}+ R

_{2})] × (+V

_{sat}) = [10kΩ/ ( 10 kΩ +11.6 kΩ)] × (+15v) = +7v The time period of the output waveform,T= 2RC ln ×[( 2R

_{1}+ R

_{2}) / ( R

_{2})] = 2× 10kΩ × 0.05 µF× ln (2×10kΩ + 11.6kΩ) / 11.6kΩ] = 1×10

^{-3}× ln2.724 = 1ms. The voltage across the capacitor will be a triangular wave form.

5. What will be the frequency of output waveform of a square wave generator if R_{2} = 1.16 R_{1}?

a) f_{o} = (1/2RC)

b) f_{o} = (ln/2RC)

c) f_{o} = (ln /2 ×√RC)

d) f_{o} = (ln/√(2 RC))

### View Answer

_{2}= 1.16 R

_{1}, then f

_{o}= 1/2RC× ln[ (2R

_{1}+ R

_{2}) / R

_{2}] = 1/2RC ×ln [(2R

_{1}+ 1.161R

_{1})/ (1.161R

_{1})] = 1/( 2RC×ln2.700)= 1/2RC.

6. What could be the possible output waveform for a free running multivibrator whose op-amp has a supply voltage of ±5v operating at 5khz?

### View Answer

_{sat}≅ +V

_{cc}=+5v and -V

_{sat}≅ -V

_{cc}=-5v. => Frequency= 5khz , f =1/t = 0.2ms.

7. Determine the output frequency for the circuit given below

a) 28.77 Hz

b) 31.97 Hz

c) 35.52 Hz

d) 39.47 Hz

### View Answer

_{o}= 1/2RC×ln [ (2R

_{1}+ R

_{2})/ R

_{2}] = 1 / {(2×33kΩ ×0.33µF)×ln[(2×33kΩ +30kΩ)/30kΩ]} = 1/ (0.02175×ln 32) = 39.47 Hz.

8. The value of series resistance in the square wave generator should be 100kΩ or higher in order to

a) Prevent excessive differential current flow

b) Increase resistivity of the circuit

c) Reduce output offset voltage

d) All of the mentioned

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9. Why zener diode is used at the output terminal of square wave generator?

a) To reduce both output and capacitor voltage swing

b) To reduce output voltage swing

c) To reduce input voltage swing

d) To reduce capacitor voltage swing

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10. A square wave oscillator has f_{o} =1khz. Assume the resistor value to be 10kΩ and find the capacitor value?

a) 3.9 µF

b) 0.3 µF

c) 2 µF

d) 0.05µF

### View Answer

_{2}= 1.16 R

_{2}, therefore the output frequency f

_{o}= 1/2RC => C = 1/2Rf

_{o}= 1/ (2×10kΩ×1khz) = 0.05µF.