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Multiple choice question for engineering

Set 1

1-4. For the given following reaction
a NH3 + b O2 → c NO2 + d H2O
1. The value of a, is?
a) 2
b) 4
c) 6
d) 8

View Answer

Answer: a [Reason:] Balance N, O and H.

2. The value of b, is?
a) 1.5
b) 2.5
c) 3.5
d) 4.5

View Answer

Answer: c [Reason:] Balance N, O and H.

3. The value of c, is?
a) 2
b) 4
c) 6
d) 8

View Answer

Answer: a [Reason:] Balance N, O and H.

4. The value of d, is?
a) 1
b) 2
c) 3
d) 4

View Answer

Answer: c [Reason:] Balance N, O and H.

5. If 1 kg of Octane is oxidised with O2, then how much kg of O2 is required?
a) 200
b) 400
c) 600
d) 800

View Answer

Answer: b [Reason:] 1 mole of Octane = 12.5 moles of O2.

6. If 1 kg of butane is burned with O2, then how much kg of CO2 will produce by 40 kg of butane?
a) 111.38
b) 121.38
c) 131.38
d) 141.38

View Answer

Answer: b [Reason:] 1 mole of butane = 4 moles of CO2.

7-8. For the given chemical reaction
C6H14 + 19/2 O2 → 6 CO2+ 7 H2O
7. If the required amount of CO2 is 440 kg/hour then how much kg of C6H14 should be burned per hour?
a) 123.33
b) 143.33
c) 163.33
d) 183.33

View Answer

Answer: b [Reason:] 1 mole of C6H14 = 6 moles of CO2.

8. If the required amount of water is 72 kg then how much C6H14 should be burned per hour?
a) 49.14
b) 39.14
c) 39.14
d) 29.14

View Answer

Answer: a [Reason:] 1 mole of C6H14 = 7 moles of H2O.

9-10. For a given chemical reaction
N2 + 3H2 → 2NH3
9. For producing 34 gms of NH3, how many moles of N2 is required?
a) 1
b) 2
c) 3
d) 4

View Answer

Answer: a [Reason:] 1 mole of N2 = 2 moles of NH3.

10. For producing 34 gms of NH3, how many gms of H2 is required?
a) 3
b) 6
c) 9
d) 12

View Answer

Answer: b [Reason:] 3 mole of H2 = 2 moles of NH3.

Set 2

1-4. For the given following reaction
a NH3 + b O2 → c NO2 + d H2O
1. The value of a, is?
a) 2
b) 4
c) 6
d) 8

View Answer

Answer: a [Reason:] Balance N, O and H.

2. The value of b, is?
a) 1.5
b) 2.5
c) 3.5
d) 4.5

View Answer

Answer: c [Reason:] Balance N, O and H.

3. The value of c, is?
a) 2
b) 4
c) 6
d) 8

View Answer

Answer: a [Reason:] Balance N, O and H.

4. The value of d, is?
a) 1
b) 2
c) 3
d) 4

View Answer

Answer: c [Reason:] Balance N, O and H.

5. If 1 kg of Octane is oxidised with O2, then how much kg of O2 is required?
a) 200
b) 400
c) 600
d) 800

View Answer

Answer: b [Reason:] 1 mole of Octane = 12.5 moles of O2.

6. If 1 kg of butane is burned with O2, then how much kg of CO2 will produce by 40 kg of butane?
a) 111.38
b) 121.38
c) 131.38
d) 141.38

View Answer

Answer: b [Reason:] 1 mole of butane = 4 moles of CO2.

7-8. For the given chemical reaction
C6H14 + 19/2 O2 → 6 CO2+ 7 H2O
7. If the required amount of CO2 is 440 kg/hour then how much kg of C6H14 should be burned per hour?
a) 123.33
b) 143.33
c) 163.33
d) 183.33

View Answer

Answer: b [Reason:] 1 mole of C6H14 = 6 moles of CO2.

8. If the required amount of water is 72 kg then how much C6H14 should be burned per hour?
a) 49.14
b) 39.14
c) 39.14
d) 29.14

View Answer

Answer: a [Reason:] 1 mole of C6H14 = 7 moles of H2O.

9-10. For a given chemical reaction
N2 + 3H2 → 2NH3
9. For producing 34 gms of NH3, how many moles of N2 is required?
a) 1
b) 2
c) 3
d) 4

View Answer

Answer: a [Reason:] 1 mole of N2 = 2 moles of NH3.

10. For producing 34 gms of NH3, how many gms of H2 is required?
a) 3
b) 6
c) 9
d) 12

View Answer

Answer: b [Reason:] 3 mole of H2 = 2 moles of NH3.

Set 3

1-5. For the given unbalanced reaction CaSO4 + NaCl → CaCl2 + Na2SO4
1. How many CaSO4 in kg is required for producing 1 mole of Na2SO4? Assume NaCl in excess.
a) 136 kg
b) 156 kg
c) 176 kg
d) 196 kg

View Answer

Answer: a [Reason:] 1 mole of CaSO4 = 1 mole of Na2SO4.

2. How many kg of Na2SO4 will be produced using 80 kg of NaCl? Assume CaSO4 in excess.
a) 122 kg
b) 142 kg
c) 162 kg
d) 182 kg

View Answer

Answer: b [Reason:] 2 mole of NaCl = 1 mole of Na2SO4.

3. How many moles of CaCl2 will be produced using 300 kg of CaSO4? Assume NaCl in excess.
a) 2.2 kg
b) 4.2 kg
c) 6.2 kg
d) 8.2 kg

View Answer

Answer: a [Reason:] 1 mole of CaCl2 = 1 mole of CaSO4.

4. How many pounds of NaCl required producing 2.5 pound moles of Na2SO4? Assume CaSO4 in excess.
a) 200
b) 400
c) 90800
d) 181600

View Answer

Answer: a [Reason:] 2 pound mole of NaCl = 1 pound mole of Na2SO4.

5. 1/A pound moles of CaSO4 are used to produce 222 kg of CaCl2. What is the value of A? Assume NaCl in excess.
a) 127
b) 227
c) 327
d) 427

View Answer

Answer: b [Reason:] 1 pound mole of CaSO4 = 1 pound mole of CaCl2.

6. When 32gms of CH4 is burned with excess oxygen, how many grams of CO2 are produced?
a) 44
b) 88
c) 132
d) 176

View Answer

Answer: b [Reason:] 1 gram mole of CH4 = 1 gm mole of CO2.

7. How many grams of C2H6 are required to produce 88 grams of CO2 when it is burned in the excess of oxygen?
a) 15
b) 30
c) 45
d) 60

View Answer

Answer: b [Reason:] 1 gram mole of C2H6 = 2 gram moles of CO2.

8-10. Nitric acid formation reaction is given as below
3NO2 + H2O → 2HNO3 + NO
8. The given reaction is
a) Balanced
b) Unbalanced
c) Partially balanced
d) None of the mentioned

View Answer

Answer: a [Reason:] Number of each element is equal on both sides.

9. For producing 4 gram moles of HNO3, how many grams of NO2 are required?
a) 274
b) 275
c) 276
d) 277

View Answer

Answer: c [Reason:] 3 gram mole of NO2 = 2 gram moles of HNO3.

10. If the NO2 in the feed is 400 gms, How many moles HNO3 will be in the product?
a) 2.797
b) 3.797
c) 4.797
d) 5.797

View Answer

Answer: d [Reason:] 3 gram mole of NO2 = 2 gram moles of HNO3.

Set 4

1-5. For the given unbalanced reaction CaSO4 + NaCl → CaCl2 + Na2SO4
1. How many CaSO4 in kg is required for producing 1 mole of Na2SO4? Assume NaCl in excess.
a) 136 kg
b) 156 kg
c) 176 kg
d) 196 kg

View Answer

Answer: a [Reason:] 1 mole of CaSO4 = 1 mole of Na2SO4.

2. How many kg of Na2SO4 will be produced using 80 kg of NaCl? Assume CaSO4 in excess.
a) 122 kg
b) 142 kg
c) 162 kg
d) 182 kg

View Answer

Answer: b [Reason:] 2 mole of NaCl = 1 mole of Na2SO4.

3. How many moles of CaCl2 will be produced using 300 kg of CaSO4? Assume NaCl in excess.
a) 2.2 kg
b) 4.2 kg
c) 6.2 kg
d) 8.2 kg

View Answer

Answer: a [Reason:] 1 mole of CaCl2 = 1 mole of CaSO4.

4. How many pounds of NaCl required producing 2.5 pound moles of Na2SO4? Assume CaSO4 in excess.
a) 200
b) 400
c) 90800
d) 181600

View Answer

Answer: a [Reason:] 2 pound mole of NaCl = 1 pound mole of Na2SO4.

5. 1/A pound moles of CaSO4 are used to produce 222 kg of CaCl2. What is the value of A? Assume NaCl in excess.
a) 127
b) 227
c) 327
d) 427

View Answer

Answer: b [Reason:] 1 pound mole of CaSO4 = 1 pound mole of CaCl2.

6. When 32gms of CH4 is burned with excess oxygen, how many grams of CO2 are produced?
a) 44
b) 88
c) 132
d) 176

View Answer

Answer: b [Reason:] 1 gram mole of CH4 = 1 gm mole of CO2.

7. How many grams of C2H6 are required to produce 88 grams of CO2 when it is burned in the excess of oxygen?
a) 15
b) 30
c) 45
d) 60

View Answer

Answer: b [Reason:] 1 gram mole of C2H6 = 2 gram moles of CO2.

8-10. Nitric acid formation reaction is given as below
3NO2 + H2O → 2HNO3 + NO
8. The given reaction is
a) Balanced
b) Unbalanced
c) Partially balanced
d) None of the mentioned

View Answer

Answer: a [Reason:] Number of each element is equal on both sides.

9. For producing 4 gram moles of HNO3, how many grams of NO2 are required?
a) 274
b) 275
c) 276
d) 277

View Answer

Answer: c [Reason:] 3 gram mole of NO2 = 2 gram moles of HNO3.

10. If the NO2 in the feed is 400 gms, How many moles HNO3 will be in the product?
a) 2.797
b) 3.797
c) 4.797
d) 5.797

View Answer

Answer: d [Reason:] 3 gram mole of NO2 = 2 gram moles of HNO3.

Set 5

1-5. a PtCl4 + b XeF2 → c PtF6 + d ClF + e Xe
For the given reaction
1. What is the value of a?
a) 1
b) 2
c) 3
d) 4

View Answer

Answer: a [Reason:] Element Balance.

2. What is the value of b?
a) 1
b) 3
c) 5
d) 7

View Answer

Answer: c [Reason:] Element Balance.

3. What is the value of c?
a) 1
b) 2
c) 3
d) 4

View Answer

Answer: a [Reason:] Element Balance.

4. What is the value of d?
a) 1
b) 2
c) 3
d) 4

View Answer

Answer: d [Reason:] Element Balance.

5. What is the value of e?
a) 1
b) 3
c) 5
d) 7

View Answer

Answer: c [Reason:] Element Balance.

6-10. For the given reaction, try to find the minimum values of balancing cofficients.
a Cr2(SO4)3 + b RbOH → c Cr(OH)3 + d Rb2SO4
6. What is the value of a?
a) 1
b) 2
c) 3
d) 4

View Answer

Answer: a [Reason:] Element Balance.

7. What is the value of b?
a) 1
b) 3
c) 6
d) 9

View Answer

Answer: c [Reason:] Element Balance.

8. What is the value of c?
a) 1
b) 2
c) 3
d) 4

View Answer

Answer: b [Reason:] Element Balance.

9. What is the value of d?
a) 1
b) 2
c) 3
d) 4

View Answer

Answer: c [Reason:] Element Balance.

10. What is the value of a+b+c+d?
a) 10
b) 12
c) 13
d) 14

View Answer

Answer: b [Reason:] Element Balance.

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