Digital Electronic MCQ Set 1
1. The objective of sharpening spatial filters is/are to _____
a) Highlight fine detail in an image
b) Enhance detail that has been blurred because of some error
c) Enhance detail that has been blurred because of some natural effect of some method of image acquisition
d) All of the mentioned
Answer
Answer: d [Reason:] Highlighting the fine detail in an image or Enhancing detail that has been blurred because of some error or some natural effect of some method of image acquisition, is the principal objective of sharpening spatial filters.
2. Sharpening is analogous to which of the following operations?
a) To spatial integration
b) To spatial differentiation
c) All of the mentioned
d) None of the mentioned
Answer
Answer: b [Reason:] Smoothing is analogous to integration and so, sharpening to spatial differentiation.
3. Which of the following fact(s) is/are true about sharpening spatial filters using digital differentiation?
a) Sharpening spatial filter response is proportional to the discontinuity of the image at the point where the derivative operation is applied
b) Sharpening spatial filters enhances edges and discontinuities like noise
c) Sharpening spatial filters deemphasizes areas that have slowly varying gray-level values
d) All of the mentioned
Answer
Answer: d [Reason:] Derivative operator’s response is proportional to the discontinuity of the image at the point where the derivative operation is applied.
Image differentiation enhances edges and discontinuities like noise and deemphasizes areas that have slowly varying gray-level values.
Since a sharpening spatial filters are analogous to differentiation, so, all the above mentioned facts are true for sharpening spatial filters.
4. Which of the facts(s) is/are true for the first order derivative of a digital function?
a) Must be nonzero in the areas of constant grey values
b) Must be zero at the onset of a gray-level step or ramp discontinuities
c) Must be nonzero along the gray-level ramps
d) None of the mentioned
Answer
Answer: c [Reason:] The first order derivative of a digital function is defined as:
Must be zero in the areas of constant grey values.
Must be nonzero at the onset of a gray-level step or ramp discontinuities.
Must be nonzero along the gray-level ramps.
5. Which of the facts(s) is/are true for the second order derivative of a digital function?
a) Must be zero in the flat areas
b) Must be nonzero at the onset and end of a gray-level step or ramp discontinuities
c) Must be zero along the ramps of constant slope
d) All of the mentioned
Answer
Answer: c [Reason:] The second order derivative of a digital function is defined as:
Must be zero in the flat areas i.e. areas of constant grey values.
Must be nonzero at the onset of a gray-level step or ramp discontinuities.
Must be zero along the gray-level ramps of constant slope.
6. The derivative of digital function is defined in terms of difference. Then, which of the following defines the first order derivative ∂f/∂x= _____ of a one-dimensional function f(x)?
a) f(x+1)-f(x)
b) f(x+1)+ f(x-1)-2f(x)
c) All of the mentioned depending upon the time when partial derivative will be dealt along two spatial axes
d) None of the mentioned
Answer
Answer: a [Reason:] The definition of a first order derivative of a one dimensional image f(x) is:
∂f/∂x= f(x+1)-f(x), where the partial derivative is used to keep notation same even for f(x, y) when partial derivative will be dealt along two spatial axes.
7. The derivative of digital function is defined in terms of difference. Then, which of the following defines the second order derivative ∂2 f/∂x2 = _____ of a one-dimensional function f(x)?
a) f(x+1)-f(x)
b) f(x+1)+ f(x-1)-2f(x)
c) All of the mentioned depending upon the time when partial derivative will be dealt along two spatial axes
d) None of the mentioned
Answer
Answer: b [Reason:] The definition of a second order derivative of a one dimensional image f(x) is:
(∂2 f)/∂x2 =f(x+1)+ f(x-1)-2f(x), where the partial derivative is used to keep notation same even for f(x, y) when partial derivative will be dealt along two spatial axes.
8. What kind of relation can be obtained between first order derivative and second order derivative of an image having a on the basis of edge productions that shows a transition like a ramp of constant slope?
a) First order derivative produces thick edge while second order produces a very fine edge
b) Second order derivative produces thick edge while first order produces a very fine edge
c) Both first and second order produces thick edge
d) Both first and second order produces a very fine edge
Answer
Answer: a [Reason:] the first order derivative remains nonzero along the entire ramp of constant slope, while the second order derivative remain nonzero only at onset and end of such ramps.
If an edge in an image shows transition like the ramp of constant slope, the first order and second order derivative values shows the production of thick and finer edge respectively.
9. What kind of relation can be obtained between first order derivative and second order derivative of an image on the response obtained by encountering an isolated noise point in the image?
a) First order derivative has a stronger response than a second order
b) Second order derivative has a stronger response than a first order
c) Both enhances the same and so the response is same for both first and second order derivative
d) None of the mentioned
Answer
Answer: b [Reason:] This is because a second order derivative is more aggressive toward enhancing sharp changes than a first order.
10. What kind of relation can be obtained between the response of first order derivative and second order derivative of an image having a transition into gray-level step from zero?
a) First order derivative has a stronger response than a second order
b) Second order derivative has a stronger response than a first order
c) Both first and second order derivative has the same response
d) None of the mentioned
Answer
Answer: c [Reason:] This is because a first order derivative has stronger response to a gray-level step than a second order, but, the response becomes same if transition into gray-level step is from zero.
11. If in an image there exist similar change in gray-level values in the image, which of the following shows a stronger response using second order derivative operator for sharpening?
a) A line
b) A step
c) A point
d) None of the mentioned
Answer
Answer: c [Reason:] second order derivative shows a stronger response to a line than a step and to a point than a line, if there is similar changes in gray-level values in an image.
Digital Electronic MCQ Set 2
1. If the Gaussian filter is expressed as H(u, v) = e(-D2 (u,v)/2D 02),where D(u, v) is the distance from point(u, v), D0 is the distance defining cutoff frequency, then for what value of D(u, v) the filter is down to 0.607 of its maximum value?
a) D(u, v) = D0
b) D(u, v) = D02
c) D(u, v) = D03
d) D(u, v) = 0
Answer
Answer: a [Reason:] For the given Gaussian filter of 2-D image, the value D(u, v) = D0 gives the filter a down to 0.607 of its maximum value.
2. State the statement as true or false. “The GLPF did produce as much smoothing as the BLPF of order 2 for the same value of cutoff frequency”.
a) True
b) False
Answer
Answer: b [Reason:] For the same value of cutoff frequency, the GLPF did not produce as much smoothing as the BLPF of order 2, because the profile of GLPF is not as tight as BLPF of order 2.
3. In general, which of the following assures of no ringing in the output?
a) Gaussian Lowpass Filter
b) Ideal Lowpass Filter
c) Butterworth Lowpass Filter
d) All of the mentioned
Answer
Answer: a [Reason:] Using Gaussian Lowpass Filter no ringing is assured, but Ideal Lowpass Filter and Butterworth Lowpass Filter of order 2and more produces significant ringing.
4. The lowpass filtering process can be applied in which of the following area(s)?
a) The field of machine perception, with application of character recognition
b) In field of printing and publishing industry
c) In field of processing satellite and aerial images
d) All of the mentioned
Answer
Answer: d [Reason:] In case of broken characters recognition system, LPF is used. LPF is used as preprocessing system in printing and publishing industry, and in case of remote sensed images LPF is used to blur out as much detail as possible leaving the large feature recognizable.
5. The edges and other abrupt changes in gray-level of an image are associated with___
a) High frequency components
b) Low frequency components
c) Edges with high frequency and other abrupt changes in gray-level with low frequency components
d) Edges with low frequency and other abrupt changes in gray-level with high frequency components
Answer
Answer: a [Reason:] High frequency components are related with the edges and other abrupt changes in gray-level of an image.
6. A type of Image is called as VHRR image. What is the definition of VHRR image?
a) Very High Range Resolution image
b) Very High Resolution Range image
c) Very High Resolution Radiometer image
d) Very High Range Radiometer Image
Answer
Answer: c [Reason:] A VHRR image is a Very High Resolution Radiometer Image.
7. The Image sharpening in frequency domain can be achieved by which of the following method(s)?
a) Attenuating the high frequency components
b) Attenuating the low-frequency components
c) All of the mentioned
d) None of the mentioned
Answer
Answer: b [Reason:] The Image sharpening in frequency domain is achieved by attenuating the low-frequency components without disturbing the high-frequency components.
8. The function of filters in Image sharpening in frequency domain is to perform reverse operation of which of the following Lowpass filter?
a) Gaussian Lowpass filter
b) Butterworth Lowpass filter
c) Ideal Lowpass filter
d) None of the Mentioned
Answer
Answer: c [Reason:] The function of filters in Image sharpening in frequency domain is to perform precisely reverse operation of Ideal Lowpass filter.
The transfer function of Highpass filter is obtained by relation: Hhp(u, v) = 1 – Hlp(u, v), where Hlp(u, v) is transfer function of corresponding lowpass filter.
9. If D0 is the cutoff distance measured from origin of frequency rectangle and D(u, v) is the distance from point(u, v). Then what value does an Ideal Highpass filter will give if D(u, v) ≤ D0 andifD(u, v) >D0?
a) 0 and 1 respectively
b) 1 and 0 respectively
c) 1 in both case
d) 0 in both case
Answer
Answer: a [Reason:] Unlike Ideal lowpass filter, an Ideal highpass filter attenuates the low-frequency components and so gives 0 for D(u, v) ≤ D0 and 1 for D(u, v) >D0.
10. What is the relation of the frequencies to a circle of radius D0, where D0 is the cutoff distance measured from origin of frequency rectangle, for an Ideal Highpass filter?
a) IHPF sets all frequencies inside circle to zero
b) IHPF allows all frequencies, without attenuating, outside the circle
c) All of the mentioned
d) None of the mentioned
Answer
Answer: c [Reason:] An Ideal high pass filter gives 0 for D(u, v) ≤ D0 and 1 for D(u, v) >D0.
11. Which of the following is the transfer function of the Butterworth Highpass Filter, of order n, D0 is the cutoff distance measured from origin of frequency rectangle and D(u, v) is the distance from point(u, v)?
a)
b)
c)
d) none of the mentioned
Answer
Answer: a [Reason:] The transfer function of Butterworth highpass filter of order n, D0 is the cutoff distance measured from origin of frequency rectangle and D(u, v) is the distance from point(u, v) is given by: .
12. Which of the following is the transfer function of the Ideal Highpass Filter? Given D0 is the cutoff distance measured from origin of frequency rectangle and D(u, v) is the distance from point(u, v).
a)
b)
c)
d) none of the mentioned
Answer
Answer: b [Reason:] The transfer function of Ideal highpass filter, whereD0 is the cutoff distance measured from origin of frequency rectangle and D(u, v) is the distance from point(u, v) is given by: .
13. Which of the following is the transfer function of the Gaussian Highpass Filter? Given D0 is the cutoff distance measured from origin of frequency rectangle and D(u, v) is the distance from point(u, v).
a)
b)
c)
d) none of the mentioned
Answer
Answer: c [Reason:] The transfer function of Gaussian highpass filter, where D0 is the cutoff distance measured from origin of frequency rectangle and D(u, v) is the distance from point(u, v) is given by: .
14. For a given image having smaller objects, which of the following filter(s), having D0 as the cutoff distance measured from origin of frequency rectangle, would you prefer for a comparably smoother result?
a) IHLF with D0 15
b) BHPF with D0 15 and order 2
c) GHPF with D0 15 and order 2
d) All of the mentioned
Answer
Answer: c [Reason:] For the same format as for BHPF, GHPF gives a result comparably smoother than BHPF. However, BHPF performance for filtering smaller object is comparable with IHPF.
15. Which of the following statement(s) is true for the given fact that “Applying Highpass filters has an effect on the background of the output image”?
a) The average background intensity increases to near white
b) The average background intensity reduces to near black
c) The average background intensity changes to a value average of black and white
d) All of the mentioned
Answer
Answer: b [Reason:] The Highpass filter eliminates the zero frequency components of the Fourier transformed image HPFs are applied on. So, the average background intensity reduces to near black.
Digital Electronic MCQ Set 3
1. Using gray-level transformation, the basic function linearity deals with which of the following transformation?
a) log and inverse-log transformations
b) negative and identity transformations
c) nth and nth root transformations
d) All of the mentioned
Answer
Answer: b [Reason:] For Image Enhancement gray-level transformation shows three basic function that are:
Linearity for negative and identity transformation
Logarithmic for log and inverse-log transformation, and
Power-law for nth and nth root transformations.
2. Using gray-level transformation, the basic function Logarithmic deals with which of the following transformation?
a) Log and inverse-log transformations
b) Negative and identity transformations
c) nth and nth root transformations
d) All of the mentioned
Answer
Answer: a [Reason:] For Image Enhancement gray-level transformation shows three basic function that are:
Linearity for negative and identity transformation
Logarithmic for log and inverse-log transformation, and
Power-law for nth and nth root transformations.
3. Using gray-level transformation, the basic function power-law deals with which of the following transformation?
a) log and inverse-log transformations
b) negative and identity transformations
c) nth and nth root transformations
d) all of the mentioned
Answer
Answer: b [Reason:] For Image Enhancement gray-level transformation shows three basic function that are:
Linearity for negative and identity transformation
Logarithmic for log and inverse-log transformation, and
Power-law for nth and nth root transformations.
4. If r be the gray-level of image before processing and s after processing then which expression defines the negative transformation, for the gray-level in the range [0, L-1]?
a) s = L – 1 – r
b) s = crᵞ, c and ᵞ are positive constants
c) s = c log (1 + r), c is a constant and r ≥ 0
d) none of the mentioned
Answer
Answer: a [Reason:] The expression for negative transformation is given as: s = L – 1 – r.
5. If r be the gray-level of image before processing and s after processing then which expression helps to obtain the negative of an image for the gray-level in the range [0, L-1]?
a) s = L – 1 – r
b) s = crᵞ, c and ᵞ are positive constants
c) s = c log (1 + r), c is a constant and r ≥ 0
d) none of the mentioned
Answer
Answer: c [Reason:] The expression for log transformation is given as: s = c log (1 + r), c is a constant and r ≥ 0.
6. If r be the gray-level of image before processing and s after processing then which expression defines the power-law transformation, for the gray-level in the range [0, L-1]?
a) s = L – 1 – r
b) s = crᵞ, c and ᵞ are positive constants
c) s = c log (1 + r), c is a constant and r ≥ 0
d) none of the mentioned
Answer
Answer: b [Reason:] The expression for power-law transformation is given as: s = crᵞ, c and ᵞ are positive constants.
7. Which of the following transformations is particularly well suited for enhancing an image with white and gray detail embedded in dark regions of the image, especially when there is more black area in the image.
a) Log transformations
b) Power-law transformations
c) Negative transformations
d) None of the mentioned
Answer
Answer: c [Reason:] Negative transformation reverses the intensity levels in the image and produces an equivalent photographic negative. So, well suited for the above given condition.
8. Which of the following transformations expands the value of dark pixels while the higher-level values are being compressed?
a) Log transformations
b) Inverse-log transformations
c) Negative transformations
d) None of the mentioned
Answer
Answer: a [Reason:] Log transformation derives a narrow range of gray-level values in input image to wider range of gray-levels in the output image, and does performs the above given transformation.
The inverse-log is applied for the opposite.
9. Although power-law transformations are considered more versatile than log transformations for compressing of gray-levels in an image, then, how is log transformations advantageous over power-law transformations?
a) The log transformation compresses the dynamic range of images
b) The log transformations reverses the intensity levels in the images
c) All of the mentioned
d) None of the mentioned
Answer
Answer: a [Reason:] For compressing gray-levels in an image, power-law transformation is more versatile than log transformation, but log transformation has an important characteristics of compressing dynamic ranges of pixels having a large variation of values.
10. A typical Fourier Spectrum with spectrum value ranging from 0 to 106, which of the following transformation is better to apply.
a) Log transformations
b) Power-law transformations
c) Negative transformations
d) None of the mentioned
Answer
Answer: a [Reason:] The log transformation compresses the dynamic range of images and so the given range turns to 0 to approx. 7, which is easily displayable with 8-bit display.
11. The power-law transformation is given as: s = crᵞ, c and ᵞ are positive constants, and r is the gray-level of image before processing and s after processing. Then, for what value of c and ᵞ does power-law transformation becomes identity transformation?
a) c = 1 and ᵞ < 1
b) c = 1 and ᵞ > 1
c) c = -1 and ᵞ = 0
d) c = ᵞ = 1
Answer
Answer: d [Reason:] For c = ᵞ = 1 the power-law transformations s = crᵞ become s = r that is an identity transformations.
12. What is gamma correction?
a) A process to remove power-law transformation response phenomena
b) A process to remove log transformation response phenomena
c) A process to correct log transformation response phenomena
d) A process to correct power-law transformation response phenomena
Answer
Answer: d [Reason:] The exponent used in power-law transformation is called gamma. So, using the ᵞ value, either ᵞ < 1 or ᵞ> 1, various responses are obtained.
13. Which of the following transformation is used cathode ray tube (CRT) devices?
a) Log transformations
b) Power-law transformations
c) Negative transformations
d) None of the mentioned
Answer
Answer: b [Reason:] The CRT devices has a power function relation between intensity and volt response.
In such devices output appears darker than input. So, gamma correction is a must in this case.
14. Log transformation is generally used in which of the following device(s)?
a) Cathode ray tube
b) Scanners and printers
c) All of the mentioned
d) None of the mentioned
Answer
Answer: d [Reason:] All the mentioned devices uses gamma correction and so power-law transformation is generally of use in such case.
15. The power-law transformation is given as: s = crᵞ, c and ᵞ are positive constants, and r is the gray-level of image before processing and s after processing. What happens if we increase the gamma value from 0.3 to 0.7?
a) The contrast increases and the detail increases
b) The contrast decreases and the detail decreases
c) The contrast increases and the detail decreases
d) The contrast decreases and the detail increases
Answer
Answer: c [Reason:] In power-law transformation as gamma decreases is increase in image details however, the contrast reduces.
Digital Electronic MCQ Set 4
1. If h(rk) = nk, rk the kth gray level and nk total pixels with gray level rk, is a histogram in gray level range [0, L – 1]. Then how can we normalize a histogram?
a) If each value of histogram is added by total number of pixels in image, say n, p(rk)=nk+n
b) If each value of histogram is subtracted by total number of pixels in image, say n, p(rk)=nk-n
c) If each value of histogram is multiplied by total number of pixels in image, say n, p(rk)=nk * n
d) If each value of histogram is divided by total number of pixels in image, say n, p(rk)=nk / n
Answer
Answer: d [Reason:] To normalize a histogram each of its value is divided by total number of pixels in image, say n. p(rk) = nk / n.
2. What is the sum of all components of a normalized histogram?
a) 1
b) -1
c) 0
d) None of the mentioned
Answer
Answer: a [Reason:] A normalized histogram. p(rk) = nk / n
Where, n is total number of pixels in image, rk the kth gray level and nk total pixels with gray level rk.
Here, p(rk) gives the probability of occurrence of rk.
3. A low contrast image will have what kind of histogram when, the histogram, h(rk) = nk, rk the kth gray level and nk total pixels with gray level rk, is plotted nk versus rk?
a) The histogram that are concentrated on the dark side of gray scale
b) The histogram whose component are biased toward high side of gray scale
c) The histogram that is narrow and centered toward the middle of gray scale
d) The histogram that covers wide range of gray scale and the distribution of pixel is approximately uniform
Answer
Answer: c [Reason:] The histogram plot is nk versus rk. So, the histogram of a low contrast image will be narrow and centered toward the middle of gray scale.
A dark image will have the histogram that are concentrated on the dark side of gray scale.
A bright image will have the histogram whose component are biased toward high side of gray scale.
A high contrast image will have the histogram that covers wide range of gray scale and the distribution of pixel is approximately uniform.
4. A bright image will have what kind of histogram, when the histogram, h(rk) = nk, rk the kth gray level and nk total pixels with gray level rk, is plotted nk versus rk?
a) The histogram that are concentrated on the dark side of gray scale
b) The histogram whose component are biased toward high side of gray scale
c) The histogram that is narrow and centered toward the middle of gray scale
d) The histogram that covers wide range of gray scale and the distribution of pixel is approximately uniform
Answer
Answer: b [Reason:] The histogram plot is nk versus rk. So, the histogram of a low contrast image will be narrow and centered toward the middle of gray scale.
A dark image will have the histogram that are concentrated on the dark side of gray scale.
A bright image will have the histogram whose component are biased toward high side of gray scale.
A high contrast image will have the histogram that covers wide range of gray scale and the distribution of pixel is approximately uniform.
5. A high contrast image and a dark image will have what kind of histogram respectively, when the histogram, h(rk) = nk, rk the kth gray level and nk total pixels with gray level rk, is plotted nk versus rk?
The histogram that are concentrated on the dark side of gray scale.
The histogram whose component are biased toward high side of gray scale.
The histogram that is narrow and centered toward the middle of gray scale.
The histogram that covers wide range of gray scale and the distribution of pixel is approximately uniform.
a) I) And II) respectively
b) III) And II) respectively
c) II) And IV) respectively
d) IV) And I) respectively
Answer
Answer: d [Reason:] The histogram plot is nk versus rk. So, the histogram of a low contrast image will be narrow and centered toward the middle of gray scale.
A dark image will have the histogram that are concentrated on the dark side of gray scale.
A bright image will have the histogram whose component are biased toward high side of gray scale.
A high contrast image will have the histogram that covers wide range of gray scale and the distribution of pixel is approximately uniform.
6. The transformation s = T(r) producing a gray level s for each pixel value r of input image. Then, if the T(r) is single valued in interval 0 ≤ r ≤ 1, what does it signifies?
a) It guarantees the existence of inverse transformation
b) It is needed to restrict producing of some inverted gray levels in output
c) It guarantees that the output gray level and the input gray level will be in same range
d) All of the mentioned
Answer
Answer: a [Reason:] The T(r) is single valued in interval 0 ≤ r ≤ 1, guarantees the existence of inverse transformation.
7. The transformation s = T(r) producing a gray level s for each pixel value r of input image. Then, if the T(r) is monotonically increasing in interval 0 ≤ r ≤ 1, what does it signifies?
a) It guarantees the existence of inverse transformation
b) It is needed to restrict producing of some inverted gray levels in output
c) It guarantees that the output gray level and the input gray level will be in same range
d) All of the mentioned
Answer
Answer: b [Reason:] A T(r) which is not monotonically increasing, could result in an output containing at least a section of inverted intensity range. The T(r) is monotonically increasing in interval 0 ≤ r ≤ 1, is needed to restrict producing of some inverted gray levels in output.
8. The transformation s = T(r) producing a gray level s for each pixel value r of input image. Then, if the T(r) is satisfying 0 ≤ T(r) ≤ 1 in interval 0 ≤ r ≤ 1, what does it signifies?
a) It guarantees the existence of inverse transformation
b) It is needed to restrict producing of some inverted gray levels in output
c) It guarantees that the output gray level and the input gray level will be in same range
d) All of the mentioned
Answer
Answer: c [Reason:] If, 0 ≤ T(r) ≤ 1 in interval 0 ≤ r ≤ 1, then the output gray level and the input gray level will be in same range.
9. What is the full form for PDF, a fundamental descriptor of random variables i.e. gray values in an image?
a) Pixel distribution function
b) Portable document format
c) Pel deriving function
d) Probability density function
Answer
Answer: d [Reason:] For a random variable, a PDF, probability density function, is one of the most fundamental descriptor.
10. What is the full form of CDF?
a) Cumulative density function
b) Contour derived function
c) Cumulative distribution function
d) None of the mentioned
Answer
Answer: c [Reason:] CDF of random variable r, gray value of input image, is cumulative distribution function.
11. For the transformation T(r) = [∫0r pr(w) dw], r is gray value of input image, pr(r) is PDF of random variable r and w is a dummy variable. If, the PDF are always positive and that the function under integral gives the area under the function, the transformation is said to be ____
a) Single valued
b) Monotonically increasing
c) All of the mentioned
d) None of the mentioned
Answer
Answer: c [Reason:] For the given transformation, the PDF being positive and the integral providing area under the function, the transformation function is single valued as well as monotonically increasing.
12. The transformation T (rk) = ∑k(j=0) nj /n, k = 0, 1, 2, …, L-1, where L is max gray value possible and r-k is the kth gray level, is called _______
a) Histogram linearization
b) Histogram equalization
c) All of the mentioned
d) None of the mentioned
Answer
Answer: c [Reason:] The given transformation is the equation for the Histogram equalization also called as Histogram linearization.
13. If the histogram of same images, with different contrast, are different, then what is the relation between the histogram equalized images?
a) They look visually very different from one another
b) They look visually very similar to one another
c) They look visually different from one another just like the input images
d) None of the mentioned
Answer
Answer: b [Reason:] This is because the contents of all images is same. The difference is just the contrast.
The histogram equalization increases the contrast and make the gray-level difference of output image visually indistinguishable.
Digital Electronic MCQ Set 5
1. The spatial coordinates of a digital image (x,y) are proportional to:
a) Position
b) Brightness
c) Contrast
d) Noise
Answer
Answer: b [Reason:] The Brightness levels are distributed over the spatial area. Hence, the spatial coordinates are proportional to brightness levels.
2. Among the following image processing techniques which is fast, precise and flexible.
a) Optical
b) Digital
c) Electronic
d) Photographic
Answer
Answer: b [Reason:] Digital image processing is more flexible and agile techniques as it is fast, accurate and reliable.
3. An image is considered to be a function of a(x,y), where a represents:
a) Height of image
b) Width of image
c) Amplitude of image
d) Resolution of image
Answer
Answer: c [Reason:] The image is a collection of dots with a definite intensity or amplitude.
4. What is pixel?
a) Pixel is the elements of a digital image
b) Pixel is the elements of an analog image
c) Pixel is the cluster of a digital image
d) Pixel is the cluster of an analog image
Answer
Answer: a [Reason:] An Image is a collection of individual points referred as pixel, thus a Pixel is the element of a digital image.
5. The range of values spanned by the gray scale is called:
a) Dynamic range
b) Band range
c) Peak range
d) Resolution range
Answer
Answer: a [Reason:] The valued spanned in gray scale image are depicted using dynamic range values.
6. Which is a colour attribute that describes a pure colour?
a) Saturation
b) Hue
c) Brightness
d) Intensity
Answer
Answer: b [Reason:] The color attribute of an image refers to the contrast of colors, which can be controlled using the Hue values.
7. Which gives a measure of the degree to which a pure colour is diluted by white light?
a) Saturation
b) Hue
c) Intensity
d) Brightness
Answer
Answer: a [Reason:] Saturation is color recognizing capability of the human eye. Hence a degree of dilution is measured using saturation.
8. Which means the assigning meaning to a recognized object.
a) Interpretation
b) Recognition
c) Acquisition
d) Segmentation
Answer
Answer: a [Reason:] The interpretation is called the assigning meaning to recognized object.
9. A typical size comparable in quality to monochromatic TV image is of size.
a) 256 X 256
b) 512 X 512
c) 1920 X 1080
d) 1080 X 1080
Answer
Answer: b [Reason:] A normal T.V have 512 x 512 resolution.
10. The number of grey values are integer powers of:
a) 4
b) 2
c) 8
d) 1
Answer
Answer: b [Reason:] The gray values are interpreted as the power of number of colors. In monochromatic image the number of colors are 2.
