Tricky MCQ set number 00255

1. Determine the relationship between log-antilog method. a) lnVx×lnVy = ln(Vx+Vy) b) lnVx / lnVy = ln(Vx-Vy) c) lnVx -lnVy = ln(Vx/Vy) d) lnVx+ lnVy = ln(Vx×Vy) AnswerAnswer: d [Reason:] The log-anilog method relies on the mathematical relationship that is the sum of the logarithm of the product of those numbers. => lnVx+lnVy = ln(Vx×Vy)….


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