## Network Theory MCQ Set 1

1. The equation of the average power (P_{avg}) is?

a) (V_{m}I_{m}/2)cosθ

b) (V_{m}I_{m}/2)sinθ

c) V_{m}I_{m}cosθ

d) V_{m}I_{m}sinθ

### View Answer

_{avg}) is P

_{avg}= (V

_{m}I

_{m}/2)cosθ.

2. Average power (P_{avg}) =?

a) V_{eff}I_{m}cosθ

b) V_{eff}I_{eff}cosθ

c) V_{m}I_{m}cosθ

d) V_{m}I_{eff}cosθ

### View Answer

_{avg}) = V

_{eff}I

_{eff}cosθ

3. In case of purely resistive circuit, the average power is?

a) V_{m}I_{m}

b) V_{m}I_{m}/2

c) V_{m}I_{m}/4

d) V_{m}I_{m}/8

### View Answer

_{m}I

_{m}/2.

4. In case of purely capacitive circuit, average power = ____ and θ=___

a) 0, 0⁰

b) 1, 0⁰

c) 1, 90⁰

d) 0, 90⁰

### View Answer

5. In case of purely inductive circuit, average power = ____ and θ=___

a) 0, 90⁰

b) 1, 90⁰

c) 1, 0⁰

d) 0, 0⁰

### View Answer

6. If a circuit has complex impedance, the average power is ______

a) power stored in inductor only

b) power stored in capacitor only

c) power dissipated in resistor only

d) power stored in inductor and power dissipated in resistor

### View Answer

7. A voltage v (t) = 100sinωt is applied to a circuit. The current flowing through the circuit is i(t) = 15sin( ωt-30⁰). Find the effective value of voltage.

a) 70

b) 71

c) 72

d) 73

### View Answer

_{eff}= V

_{m}/√2. Given V

_{m}= 100. On substituting the value in the equation we get effective value of voltage = 100/√2 = 71V.

8. Find the effective value of current in the question 7.

a) 9

b) 10

c) 11

d) 12

### View Answer

_{eff}= I

_{m}/√2. Given I

_{m}= 15. On substituting the value in the equation we get effective value of current = 15/√2=11V.

9. Determine the average power delivered to the circuit.

a) 620

b) 630

c) 640

d) 650

### View Answer

_{avg}= V

_{eff}I

_{eff}cosθ, θ = 30⁰. We have V

_{eff}= 71, I

_{eff}= 11. So the average power delivered to the circuit P

_{avg}= 71 x 11 x cos 30⁰ = 650W.

10. Determine the average power delivered to the circuit consisting of an impedance Z = 5+j8 when the current flowing through the circuit is I = 5∠30⁰.

a) 61.5

b) 62.5

c) 63.5

d) 64.5

### View Answer

_{avg}= I

_{m}

^{2}R/2. Given I

_{m}= 5, R = 5.So the average power delivered to the circuit = 5

^{2}×5/2 = 62.5W.

## Network Theory MCQ Set 2

1. The expression of power (P_{1}) at lower half power frequency is?

a) (I^{2}_{max}R)/8

b) (I^{2}_{max}R)/4

c) (I^{2}_{max}R)/2

d) I^{2}_{max}R

### View Answer

_{1}) at lower half power frequency is P

_{1}= (I

^{2}

_{max}R)/2.

2. At upper half power frequency, the expression for power (P_{2}) is?

a) I^{2}_{max}R

b) (I^{2}_{max}R)/2

c) (I^{2}_{max}R)/4

d) (I^{2}_{max}R)/8

### View Answer

_{2}) is P

_{2}= (I

^{2}

_{max}R)/2. The response curve is also called the selectivity curve of the circuit.

3. Determine the resonant frequency for the specifications: R = 10Ω, L = 0.1H, C = 10µF.

a) 157

b) 158

c) 159

d) 160

### View Answer

_{r}= 1/(2π√LC). On substituting the given values we get resonant frequency = 1/(2π√(0.1×10×10

^{-6}))=159.2 Hz.

4. The expression for lower half power frequency is?

a) (-R+√(x^{2}+4LC))/4πL

b) (–R-√(x^{2}+4LC))/4πL

c) (R-√(x^{2}+4LC))/4πL

d) (R+√(x^{2}+4LC))/4πL

### View Answer

_{C}> X

_{L}(1/2πf

_{1}C)-2πf

_{1}L=R. f

_{1}= (-R+√(x

^{2}+4LC))/4πL.

5. The expression for upper half power frequency is?

a) (R+√(x^{2}+4LC))/4πL

b) (R-√(x^{2}+4LC))/4πL

c) (–R-√(x^{2}+4LC))/4πL

d) (-R+√(x^{2}+4LC))/4πL

### View Answer

_{C}< X

_{L}=> -(1/2πf

_{2}C)+2πf

_{2}L=R. f

_{2}= (R+√(x

^{2}+4LC))/4πL.

6. The expression for bandwidth is?

a) R/πL

b) R/2πL

c) R/4πL

d) R/8πL

### View Answer

_{2}– f

_{1}= R/2πL.

7. In series circuits, the expression for quality factor is?

a) f_{r}

b) BW

c) f_{r}/BW

d) BW/ f_{r}

### View Answer

_{r}/BW.

8. In a series circuit having resistance and inductance, the quality factor is?

a) ωL/R

b) R/ωL

c) ωL

d) R

### View Answer

9. If a series circuit contains resistor and capacitor, the expression for quality factor is?

a) C

b) ωRC

c) ωC

d) 1/ωRC

### View Answer

10. The quality factor of the coil for a series circuit having R = 10Ω, L = 0.1H, C = 10µF.

a) 1

b) 5

c) 10

d) 15

### View Answer

_{r}= 1/(2π√LC)=1/(2π√(0.1×10×10

^{-6}))=159.2 Hz. The relation between quality factor, resonant frequency and bandwidth is Q = fr/BW = 2πfrL/R = (6.28×159.2×0.1)/10=10.

## Network Theory MCQ Set 3

1. The resistance element __________ while going from the time domain to frequency domain.

a) does not change

b) increases

c) decreases

d) increases exponentially

### View Answer

2. The relation between current and voltage in case of inductor is?

a) v=Ldt/di

b) v=Ldi/dt

c) v=dt/di

d) v=di/dt

### View Answer

_{o}. The time domain relation between current and voltage is v=Ldi/dt.

3. The s-domain equivalent of the inductor reduces to an inductor with impedance?

a) L

b) sL

c) s^{2}L

d) s^{3}L

### View Answer

4. The voltage and current in a capacitor are related as?

a) i=Cdt/dv

b) v=Cdv/dt

c) i=Cdv/dt

d) v=Cdt/dv

### View Answer

_{o}. The voltage current relation in the time domain is i=Cdv/dt.

5. The s-domain equivalent of the capacitor reduces to an capacitor with impedance?

a) sC

b) C

c) 1/C

d) 1/sC

### View Answer

6. From the circuit shown below, find the value of current in the loop.

a) (V/R)/(s+1/RC)

b) (V/C)/(s+1/R)

c) (V/C)/(s+1/RC)

d) (V/R)/(s+1/R)

### View Answer

7. After taking the inverse transform of current in the circuit shown in question 6, the value of current is?

a) i=(V/C)e^{-t/R}

b) i=(V/C)e^{-t/RC}

c) i=(V/R)e^{-t/RC}

d) i=(V/R)e^{-t/R}

### View Answer

_{o}volts. By taking the inverse transform of the current, we get i=(V/R) e

^{-t/RC}.

8. The voltage across the resistor in the circuit shown in question 6 is?

a) Ve^{t/R}

b) Ve^{-t/RC}

c) Ve^{-t/R}

d) Ve^{t/RC}

### View Answer

^{-t/RC}.

9. The voltage across the resistor in the parallel circuit shown is?

a) V/(s-1/R)

b) V/(s-1/RC)

c) V/(s+1/RC)

d) V/(s+1/C)

### View Answer

10. Taking the inverse transform of the voltage across the resistor in the circuit shown in question 9.

a) Ve^{-t/τ}

b) Ve^{t/τ}

c) Ve^{tτ}

d) Ve^{-tτ}

### View Answer

^{-t/RC}=Ve

^{-t/τ}, where τis the time constant and τ = RC. And v is the voltage across the resistor.

## Network Theory MCQ Set 4

1. Potential difference in electrical terminology is known as?

a) Voltage

b) Current

c) Resistance

d) Conductance

### View Answer

2. The circuit in which current has a complete path to flow is called ______ circuit.

a) short

b) open

c) closed

d) open loop

### View Answer

3. If the voltage-current characteristics is a straight line through the origin, then the element is said to be?

a) Linear element

b) Non-linear element

c) Unilateral element

d) Bilateral element

### View Answer

4. The voltage across R_{1} resistor in the circuit shown below is?

a) 10

b) 5

c) 2.5

d) 1.25

### View Answer

_{1}and R

_{2}. So the voltage across R

_{1}will be 5v.

5. The energy stored in the inductor is?

a) Li²/4

b) Li²/2

c) Li²

d) Li²/8

### View Answer

6. How many types of dependent or controlled sources are there?

a) 1

b) 2

c) 3

d) 4

### View Answer

7. Find the voltage V_{x} in the given circuit.

a) 10

b) 20

c) 30

d) 40

### View Answer

_{x}=> V

_{x}= 10V.

8. If the resistances 1Ω, 2Ω, 3Ω, 4Ω are parallel, then the equivalent resistance is?

a) 0.46Ω

b) 0.48Ω

c) 0.5Ω

d) 0.52Ω

### View Answer

_{t}= (1/R

_{1})+(1/R

_{2})+(1/R

_{3})+(1/R

_{4}). And R

_{1}, R

_{2}, R

_{3}, R

_{4}are 1Ω, 2Ω, 3Ω, 4Ω respectively. => R

_{t}= 0.48Ω.

9. Find total current(mA) in the circuit.

a) 1

b) 2

c) 3

d) 4

### View Answer

_{2}is parallel to R

_{3}. So equivalent resistance of R

_{2}and R

_{3}is 1K. The total resistance in the circuit is (1+1+1)K= 3K.Current in the circuit is 3V/3KΩ= 1mA.

10. If the resistances 3Ω, 5Ω, 7Ω, 9Ω are in series, then their equivalent resistance(Ω) is?

a) 9

b) 20

c) 24

d) 32

### View Answer

## Network Theory MCQ Set 5

1. The solution of differential equations for networks is of the form?

a) i(t)=K_{n} e^{(sn t)}

b) i(t)=K_{n} e^{(-sn t)}

c) i(t)=-K_{n} e^{(-sn t)}

d) i(t)=-K_{n} e^{(sn t)}

### View Answer

_{n}e

^{(sn t)}where S

_{n}is a complex number which is a root of the characteristic equation.

2. The real part of the complex frequency is called?

a) radian frequency

b) neper frequency

c) sampling frequency

d) angular frequency

### View Answer

3. The imaginary part of the complex frequency is called?

a) angular frequency

b) sampling frequency

c) neper frequency

d) radian frequency

### View Answer

4. The ratio of transform voltage to the transform current is defined as _________ of the resistor.

a) transform voltage

b) transform current

c) transform impedance

d) transform admittance

### View Answer

_{R}(s) = V

_{R}(s)/I

_{R}(s) =R.

5. The ratio of transform current to the transform voltage is defined as ________ of the resistor.

a) transform admittance

b) transform impedance

c) transform current

d) transform voltage

### View Answer

_{R}(s) = I

_{R}(s)/V

_{R}(s) =G.

6. The transform impedance of the inductor is?

a) L

b) 1/L

c) sL

d) 1/sL

### View Answer

_{1}(s) we have the transform impedance of the inductor. The transform impedance of the inductor is Z

_{L}(s) = V

_{1}(s)/I

_{L}(s) = sL.

7. The transform admittance of the inductor is?

a) 1/sL

b) sL

c) 1/L

d) L

### View Answer

_{L}(s) = I

_{1}(s)/V

_{L}(s) = 1/sL where I

_{1}(s) is the total transform current through the inductor L.

8. The equivalent transform circuit contains an admittance of value ____ and equivalent transform current source.

a) 1/L

b) 1/sL

c) L

d) sL

### View Answer

_{L}(0

^{+}). The equivalent transform circuit contains an admittance of value 1/sL and equivalent transform current source.

9. The transform impedance of the capacitor is?

a) C

b) 1/C

c) sC

d) 1/sC

### View Answer

_{1}(s) to the transform current I

_{C}(s) and is Z

_{C}(s) = 1/Cs.

10. The transform admittance of the capacitor is?

a) 1/sC

b) sC

c) 1/C

d) C

### View Answer

_{1}(s) to transform voltage V

_{C}(s) and is Y

_{C}(s) = sC.