# Multiple choice question for engineering

## Set 1

1. The determination of the internal loading in the beams is usually done so as to ______________

a) Break the beam

b) Know the length

c) Know the diameter

d) Design the beam

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2. The slope of the shear diagram is equal to__________

a) Rotational moment

b) Bending moment

c) Total weight

d) Distributed load intensity

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3. The shear diagram will jump downward if the _________________

a) Rotational moment

b) Bending moment

c) Total weight

d) Force will act downwards

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4. Change in the shear is equal to ____________

a) Rotational moment

b) Bending moment

c) Total weight

d) Area under loading curve

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5. The internal loading can be found by ________________________

a) Distributed load method

b) Method of area

c) Method of line

d) Method of volume

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6. The equation of change in moment equals area under shear diagram is not applied when_________

a) Rotational moment

b) Bending moment

c) Total weight

d) Couple moment acts

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7. Slope of the moment diagram is equal to _________

a) Rotational moment

b) Bending moment

c) Total weight

d) Shear

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8. The change in moment is equal to _________

a) Rotational moment

b) Bending moment

c) Total weight

d) Area under shear diagram

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9. In the making of the shear force diagram or the bending moment diagrams, one method is used, distributed load. In this the distributed load will be considered positive if ____________

a) Loading acts upward

b) Loading acts downward

c) Loading acts rightward

d) Loading acts leftward

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10. Determine the shear force of the beam shown.

a) 450N

b) 50N

c) 40N

d) 45N

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11. The shear diagram will jump upwards if there is __________

a) Rotational moment

b) Bending moment

c) Total weight

d) Change in shear is positive

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12. The equation of change in moment equals area under shear diagram is not applied when?

a) Rotational moment

b) Bending moment

c) Total weight

d) A concentrated force acts

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13. The couple in the beam is simplified easily by the help of right hand rule. But the forces simplification is not possible as there is no such system of rules so that the forces can be simplified.

a) The first part of the statement is false and other part is true

b) The first part of the statement is false and other part is false too

c) The first part of the statement is true and other part is false

d) The first part of the statement is true and other part is true too

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14. The couple moment and the force is divided to get the distance of the axis from the point of action of the force.

a) True

b) False

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15. Determine the normal force of the beam shown.

a) 0N

b) 50N

c) 40N

d) 45N

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## Set 2

1. Potential energy is stored in the body if some work is done on it. Work done is best given by:

a) dU = Fdrcosθ

b) dU = Fdrsinθ

c) dU = Fdrcotθ

d) dU = Fdrdθ

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2. If a block moves from a height h above the ground then the potential energy is given by_____

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3. Potential energy stored in a spring to a body from moving it from x1 to x 2 distances is given by_____

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4. For equilibrium the net moment acting on the body by various forces is zero, in any of the body in the space, as in the space it is acted by various forces, like gravity.

a) True

b) False

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5. We use sometimes the measures to know the direction of moment in the calculations of the moments caused by the gravitational forces over the body above the ground level. Which one is right about it(consider the mentioned axis to be positive)?

a) Thumb is z-axis, fingers curled from x-axis to y-axis

b) Thumb is x-axis, fingers curled from z-axis to y-axis

c) Thumb is y-axis, fingers curled from x-axis to z-axis

d) Thumb is z-axis, fingers curled from y-axis to x-axis

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6. Determine the magnitude of the force F = 300j parallel to the direction of AB?

a) 155N

b) 257.1N

c) 200N

d) 175N

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7. Which statement is correct about the vector F in the showing the gravitational nature of the forces?

a) F= Fcos β + Fcos α + Fcosγ

b) F= Fsin β + Fcos α + Fcosγ

c) F= Fcos β + Fsin α + Fcosγ

d) F= Fcos β + Fcos α + Fsinγ

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8. What is the value of θ in the figure given below ?

a) 69˚

b) 60˚

c) 55˚

d) 90˚

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9. Air also resist the body in the motion. The maximum value of the frictional force is called _________

a) Limiting Friction

b) Non-Limiting Friction

c) Limiting Action Friction

d) Non-Limiting Action Friction

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10. The coefficient of kinetic friction when a body is moving from a height above the ground level to a smaller height is ____________ than coefficient of static friction.

a) Smaller

b) Larger

c) Significantly larger

d) Highly larger

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11. Free body diagrams doesn’t play any role in making the calculations on the conditions of the equilibrium of the body when there is the involvement of the potential energy.

a) True

b) False

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12. The net forces of acting on the body needs to be zero. This is also applicable for the bodies having some potential energy. This means that the work done over it is saved in the form of potential energy.

a) True

b) False

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13. Virtual Work done is saved in the form of potential energy. It is best given by ___________

a) δU = Fδrcosθ

b) δU = Fδrsinθ

c) δU = Fδrcotθ

d) δU = Fδrδθ

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14. Which of the following is correct for the forces which are considered in the potential energy calculations?

a) The application of the conditions of the equilibrium of the body is valid only if the forces are collinear

b) The application of the conditions of the equilibrium of the body is valid only if the forces are parallel

c) The application of the conditions of the equilibrium of the body is valid only if the forces are perpendicular

d) The application of the conditions of the equilibrium of the body is valid throughout

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15. For the conditions of the equilibrium of the body, i.e. the rigid body only the external forces defines the equilibrium. And the support reactions only cancels out the rotation part of the body and thus the potential energy of the body is stored in it.

a) The first part of the statement is false and other part is true

b) The first part of the statement is false and other part is false too

c) The first part of the statement is true and other part is false

d) The first part of the statement is true and other part is true too

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## Set 3

1. What does the Newton’s third law states?

a) The rate of change of momentum is equal to the force applied

b) For every reaction there is an opposite reaction

c) The body is tend to be rotated if the force is applied tangentially

d) The body is rest until a force is applied

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2. The net force of the body is zero that means the force are not being applied to the body at all and hence the body is in equilibrium.

a) The first part of the statement is false and other part is true

b) The first part of the statement is false and other part is false too

c) The first part of the statement is true and other part is false

d) The first part of the statement is true and other part is true too

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3. In the simplification of the forces for the free body diagram the net force acts at the ___________ of the loading body.

a) Centroid

b) The centre axis

c) The corner

d) The base

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4. For a vector F, Fcosβ is equal to zero. What does this refer?

a) X-axis component is zero

b) Y-axis component is zero

c) Z-axis component is zero

d) β = 180˚

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5. As in the determination of the various unknown forces in the free body diagram involves the use of vectors. So one of the vector law is commutative law and it is valid for the cross product of two vectors. (Commutative law: PxQ = QxP; for two vectors P and Q)

a) True

b) False

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6. As the free body diagram of the problem statement involves the use of forces. So in them the ___________ forces do not cause the rotation.

a) Non-concurrent

b) Concurrent

c) Parallel

d) Non-Parallel

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7. For equilibrium the normal forces acts in which direction in the free body diagrams if they are constructed for the friction part calculations?

a) Vertically Upward

b) Vertically Downward

c) Horizontally Right

d) Horizontally Left

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8. Which of the following is the assumption on the property of the surface on which block is present in case we are dealing with the calculations involving the friction?

a) Non-rigid

b) Coloured red

c) Having density in negative

d) The motion of that block is always horizontal

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9. Calculate the Normal force developed between the body and the surface.

a) 611N

b) 116N

c) 100N

d) 180N

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10. There are three types of friction problems. One of them is _____________

a) Impending motion at a single point of contact

b) No-Impending motion at a single point of contact

c) Impending motion at a all points of contact

d) Apparent Impending motion

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11. The phenomena of horizontal pull and push explains something related to the friction, among the following what is it?

a) Theory of friction

b) Theory of relativity

c) Theory of action

d) Theory of forces

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12. There are main two types of forces which are being stated in the free body diagram, and they are generally the resultant of various forces which are being acted over the body. Which are they?

a) Normal and Frictional

b) Normal and Vertical

c) Vertical and Frictional

d) Normal and Fractional

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13. The frictional force is directly proportional to the surface of the solid.

a) True

b) False

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14. Calculate the frictional force developed between the body and the surface.

a) 160N

b) 16N

c) 10N

d) 180N

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15. The frictional force developed always acts ____________ to the surface of the application of the friction.

a) Tangential

b) Perpendicular

c) Parallel

d) Normal

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## Set 4

1. The product of Inertia for an area is required so as to _____________

a) Determine Maximum moments of inertia for an Area

b) Determine Maximum moments of inertia for a Line

c) Determine Maximum moments of inertia for a Volume

d) Determine Maximum moments of inertia for a Rectangle

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2. Determine the product of inertia for the triangle in the given figure.

a) (bh)^{2}/8

b) (bh)^{2}/16

c) (bh)^{2}/2

d) (bh)^{2}/4

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3. Moment of Inertia is the integration of the square of the distance of the centroid and the del area along the whole area of the structure and after these calculations we multiply the moment of areas.

a) True

b) False

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4. There is perpendicular axis theorem for the area, and it is can be used to determine the product of moment of inertia.

a) True

b) False

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5. What is parallel axis theorem and to whom it is applied so that it can give the product of inertia of an area?

a) Theorem used to add the two mutually perpendicular moment of inertias for areas

b) Theorem used to add the two mutually perpendicular moment of inertias for volumes

c) Theorem used to add the two mutually perpendicular moment of inertias for linear distances

d) Theorem used to add the two mutually perpendicular moment of inertias for vectors

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6. The product of moment of inertia is the sum of _____________ and _________________

a) Area and volume

b) Volume and linear distance

c) Moment of inertia at centroid and the product of the area and del dx and del dy

d) Moment of inertia at base and the product of the area and del dx and del dy

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7. The distance in the parallel axis theorem for the use in the determination of the product of moment of inertia is multiplied by:

a) Area

b) Volume

c) Linear distance

d) Area/Volume

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8. One of the use of the centre of mass or centroid is as in the determination of the product of moment of inertia is that the net force acts at the ___________ of the loading body.

a) Centroid

b) The centre axis

c) The corner

d) The base

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9. The product of Inertia for an area is helpful so as to _____________

a) Determine Minimum moments of inertia for an Area

b) Determine Maximum moments of inertia for a Line

c) Determine Minimum moments of inertia for a Volume

d) Determine Maximum moments of inertia for a Rectangle

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10. Determine the del product of inertia for the triangle in the given figure used for the calculations.

a) dIxy=(h^{2}/2b^{2})x^{3}dx

b) dIxy=(h/2b2)x^{3}dx

c) dIxy=(h^{2}/2)x^{3}dx

d) dIxy=(h^{2}/b2)x^{3}dx

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11. If the non-Uniform loading is of the type of parabola then for calculating the product of moment of inertia for areas?

a) The net load will not be formed as all the forces will be cancelled

b) The net force will act the centre of the parabola

c) The net force will act on the base of the loading horizontally

d) The net force will act at the centroid of the parabola

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12. If any external force also is applied on the structure and we are determining the product of moment of inertia then what should we consider?

a) The net force will act at the centroid of the structure only

b) The net load will not be formed as all the forces will be cancelled

c) The net force will act on the base of the loading horizontally

d) The net force will not to be considered, there would be a net force of the distribution, rest will be the external forces

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13. The body is sometimes acted by two or three force members and we need to find the product of moment of inertia for the same. The difference between the two and the three force members is:

a) The former is collinear and the latter is parallel

b) The former is parallel and the latter is perpendicular

c) The former is perpendicular and the latter is collinear

d) The former is acting on two points in the body while the latter is on three points

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14. Whenever the distributed loading acts perpendicular to an area its intensity varies __________ for the determination of the product of moment of inertia.

a) Linearly

b) Non-Linearly

c) Parabolically

d) Cubically

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15. The calculation of the product of moment of the body due to the loadings involve a quantity called ____________

a) Moment

b) Inertia

c) Moment of Inertia

d) Rotation

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## Set 5

1. Free body diagrams doesn’t play any role in making the calculations on the conditions of the equilibrium of the body.

a) True

b) False

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2. The net forces of acting on the body needs to be zero. This is also applicable for the simply supported beams. This means that the support reaction are also counted in making the net force zero.

a) True

b) False

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3. Determine the horizontal components of the reaction on the beam caused by the pin at Q.

a) 268N

b) 68N

c) 28N

d) 288N

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4. If the body is in equilibrium, but it having a rotational curled ray shown in the free body diagram then:

a) The diagram is wrong

b) Such rotations can’t be shown in the fbds(free body diagrams)

c) The ray shown may be correct, but the body is not said to be in equilibrium

d) The body is said to be in equilibrium only, as the other forces will cancel out that rotation

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5. If five forces are acting on the single particle and having an angle of 72˚ between each and are collinear, then:

a) The net force acting on the body is zero

b) The net force acting on the body is horizontal

c) The net force acting on the body is vertical

d) The net force acting on the body is at an angle of 45

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6. Which of the following is correct?

a) There is only one type of support for the beams

b) There are only two types of support for the beams

c) There are only three types of support for the beams

d) There are various types of support for the beams and they are countless

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7. What does the Newton’s second law states?

a) The rate of change of momentum is equal to the force applied

b) For every reaction there is an opposite reaction

c) The body is tend to be rotated if the force is applied tangentially

d) The body is rest until a force is applied

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8. Determine the vertical components of the reaction on the beam caused by the pin at Q.

a) 286N

b) 68N

c) 28N

d) 288N

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9. Which of the following is correct?

a) The application of the conditions of the equilibrium of the body is valid only if the forces are collinear

b) The application of the conditions of the equilibrium of the body is valid only if the forces are parallel

c) The application of the conditions of the equilibrium of the body is valid only if the forces are perpendicular

d) The application of the conditions of the equilibrium of the body is valid throughout

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10. Determine the horizontal components of the reaction on the beam caused by the pin at Q. The force 60N is multiplied by 10 and then is applied.

a) 0N

b) 445N

c) 45N

d) 40N

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11. For the conditions of the equilibrium of the body, i.e. the rigid body only the external forces defines the equilibrium. And the support reactions only cancels out the rotation part of the body.

a) The first part of the statement is false and other part is true

b) The first part of the statement is false and other part is false too

c) The first part of the statement is true and other part is false

d) The first part of the statement is true and other part is true too

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12. Cantilever beams are always in equilibrium, whether you form the equilibrium equations or not.

a) True

b) False

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13. Determine the horizontal components of the reaction on the beam caused by the pin at Q.

a) 268N

b) 68N

c) 28N

d) 288N

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14. Determine the vertical components of the reaction on the beam caused by the pin at Q. The force 60N is multiplied by 10 and then is applied.

a) 319N

b) 445N

c) 45N

d) 40N

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15. For the conditions of the equilibrium of the body, i.e. the rigid body only the external forces defines the equilibrium. And the support reactions only adds the rotation part of the body.

a) The first part of the statement is false and other part is true

b) The first part of the statement is false and other part is false too

c) The first part of the statement is true and other part is false

d) The first part of the statement is true and other part is true too