# Multiple choice question for engineering

## Set 1

1. The given numbers are shown with their significant figures respectively. Find out the wrong one option?

a) 26.24 and 4

b) 24000. and 5

c) 0.000460 and 3

d) 28000.0 and 5

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2. The theoretical production rate of a chemical is 1µg/(mL)(min.). What is the actual production rate of the chemical in lb mol/ (day)(ft3) with an efficiency of 98%?

a) 0.0880

b) 0.0800

c) 0.0449

d) 0.529

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3. Standard form of 2145.67 is

a) 2.14*10^{3}

b) 2.14567*10^{3}

c) 0.214*10^{4}

d) None of the mentioned

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^{3}.

4. Correctly rounded, the quotient 5.000 g / 50.0 mL is

a) 0.10 g/mL

b) 0.1 g/mL

c) 0.100 g/mL

d) 0.1000 g/mL

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5. Correctly rounded, the product 3.000 cm × 30.0 cm is

a) 9.0 x 10^{1} cm^{2}

b) 9.000 x 10^{1} cm^{2}

c) 9 x 10^{1} cm^{2}

d) 9.00 x 10^{1} cm^{2}

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6. Number of digits that are reasonably sure, called significant figures.

Above given definition is

a) Correct

b) Incorrect

c) Probably correct

d) None of the mentioned

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7. 0.009046879855, round off the number to three significant figures

a) 0.0905

b) 0.0904

c) 0.09046

d) 0.09035

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8. How many significant numbers are there in 420?

a) 1

b) 2

c) 3

d) 0

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9. Using the proper number of significant figures 6 X 6 equals to

a) 3

b) 4

c) 36

d) 40

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10. How many significant figures are there in 0.002000?

a) 1

b) 2

c) 3

d) 4

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## Set 2

1-5. For a given reaction

C_{2}H_{6} + Cl_{2} → C_{2}H_{5}Cl + HCl

Assume that the percentage conversion of the limiting reactant is 60% and the feed composition in mole percent is 50% C_{2}H_{6}, 40% Cl_{2} and 10% N_{2}.

1. What is the mole percent of C_{2}H_{6} in the product?

a) 24

b) 26

c) 40

d) 60

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2. What is the mole percent of Cl_{2} in the product?

a) 16

b) 24

c) 26

d) 40

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3. What is the mole percent of C_{2}H_{5}Cl in the product?

a) 16

b) 24

c) 26

d) 40

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_{2}H

_{5}Cl produced in the reaction = 24 moles.

4. What is the mole percent of HCl in the product?

a) 16

b) 24

c) 26

d) 40

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5. What is the mole percent of N_{2} in the product?

a) 10

b) 16

c) 24

d) 40

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_{2}is not involved in the reaction, Moles of N

_{2}= 10 moles.

6-10. In a bioreactor, these following reaction can occur to perform the fermentation process-

C_{6}H_{12}O_{6} → 2C_{2}H_{5}OH + 2CO_{2}

C_{6}H_{12}O_{6} → 2C2H3CO_{2}H + 2H_{2}O

The tank is initially charged with 6000 kg of 15% solution of glucose in water. After fermentation, 160 kg of CO_{2} produced and 100 kg of unreacted glucose left in the broth.

6. How much water is there in the tank after fermentation?

a) 94.45 kg

b) 5100 kg

c) 5194.45 kg

d) None of the mentioned

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7. How many moles of C_{6}H_{12}O_{6} reacted in the first reaction?

a) 1.414

b) 1.818

c) 2.424

d) 4.848

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8. How much Ethanol is there in the product in kgs?

a) 67.43

b) 167.43

c) 267.43

d) 367.43

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9. How much propenoic acid is there in the product in kgs?

a) 178

b) 278

c) 378

d) 478

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10. How many kgs of C_{6}H_{12}O_{6} is used in second reaction?

a) 127.54

b) 227.54

c) 327.54

d) 427.54

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## Set 3

1-5. For a given reaction

C_{2}H_{6} + Cl_{2} → C_{2}H_{5}Cl + HCl

Assume that the percentage conversion of the limiting reactant is 60% and the feed composition in mole percent is 50% C_{2}H_{6}, 40% Cl_{2} and 10% N_{2}.

1. What is the mole percent of C_{2}H_{6} in the product?

a) 24

b) 26

c) 40

d) 60

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2. What is the mole percent of Cl_{2} in the product?

a) 16

b) 24

c) 26

d) 40

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3. What is the mole percent of C_{2}H_{5}Cl in the product?

a) 16

b) 24

c) 26

d) 40

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_{2}H

_{5}Cl produced in the reaction = 24 moles.

4. What is the mole percent of HCl in the product?

a) 16

b) 24

c) 26

d) 40

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5. What is the mole percent of N_{2} in the product?

a) 10

b) 16

c) 24

d) 40

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_{2}is not involved in the reaction, Moles of N

_{2}= 10 moles.

6-10. In a bioreactor, these following reaction can occur to perform the fermentation process-

C_{6}H_{12}O_{6} → 2C_{2}H_{5}OH + 2CO_{2}

C_{6}H_{12}O_{6} → 2C2H3CO_{2}H + 2H_{2}O

The tank is initially charged with 6000 kg of 15% solution of glucose in water. After fermentation, 160 kg of CO_{2} produced and 100 kg of unreacted glucose left in the broth.

6. How much water is there in the tank after fermentation?

a) 94.45 kg

b) 5100 kg

c) 5194.45 kg

d) None of the mentioned

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7. How many moles of C_{6}H_{12}O_{6} reacted in the first reaction?

a) 1.414

b) 1.818

c) 2.424

d) 4.848

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8. How much Ethanol is there in the product in kgs?

a) 67.43

b) 167.43

c) 267.43

d) 367.43

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9. How much propenoic acid is there in the product in kgs?

a) 178

b) 278

c) 378

d) 478

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10. How many kgs of C_{6}H_{12}O_{6} is used in second reaction?

a) 127.54

b) 227.54

c) 327.54

d) 427.54

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## Set 4

1. The given statement for stoichiometry is

“Stoichiometry provides a quantitative means of relating the amount of products produced by a chemical reaction to amount of reaction and vice versa.”

a) True

b) False

c) Insufficient information to predict

d) None of the mentioned

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2. The law of _____________ states that chemical reactions proceed with fix ratios of the number of reactant and products and products involved in the reaction.

a) Mass Conservation

b) Mole Conservation

c) Constant Proportionality

d) None of the mentioned

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3-5. C6H12O6 + a O2 → b CO2 + c H2O

For the above given reaction

3. What is the value of a?

a) 2

b) 4

c) 6

d) 8

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4. What is the value of b?

a) 2

b) 4

c) 6

d) 8

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5. What is the value of c?

a) 2

b) 4

c) 6

d) 8

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For the given balanced reaction

C6H12O6 + 6 O2 → 6 CO2 + 6 H2O (Mol. Wt. of Glucose = 180)

In the below given questions if there is not specified the amount of a component then consider that in excess.

6. For 360 gms of Glucose how many gms of O2 is required?

a) 124

b) 284

c) 308

d) 384

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7. For producing 6 mole of H2O, how many Kgs of Glucose is required?

a) 180

b) 360

c) 540

d) 720

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8. If the amount of CO2 produced is 44 gms, then How many Kgs of Glucose was in the feed?

a) 30

b) 60

c) 90

d) 120

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9. By taking 360 gms of Glucose how many gms of CO2 can be produced?

a) 228

b) 328

c) 428

d) 528

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10. By taking 64 gms of O2, How many gms of H2O can be produced?

a) 18

b) 36

c) 54

d) 72

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## Set 5

1. The given statement for stoichiometry is

“Stoichiometry provides a quantitative means of relating the amount of products produced by a chemical reaction to amount of reaction and vice versa.”

a) True

b) False

c) Insufficient information to predict

d) None of the mentioned

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2. The law of _____________ states that chemical reactions proceed with fix ratios of the number of reactant and products and products involved in the reaction.

a) Mass Conservation

b) Mole Conservation

c) Constant Proportionality

d) None of the mentioned

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3-5. C6H12O6 + a O2 → b CO2 + c H2O

For the above given reaction

3. What is the value of a?

a) 2

b) 4

c) 6

d) 8

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4. What is the value of b?

a) 2

b) 4

c) 6

d) 8

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5. What is the value of c?

a) 2

b) 4

c) 6

d) 8

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For the given balanced reaction

C6H12O6 + 6 O2 → 6 CO2 + 6 H2O (Mol. Wt. of Glucose = 180)

In the below given questions if there is not specified the amount of a component then consider that in excess.

6. For 360 gms of Glucose how many gms of O2 is required?

a) 124

b) 284

c) 308

d) 384

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7. For producing 6 mole of H2O, how many Kgs of Glucose is required?

a) 180

b) 360

c) 540

d) 720

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8. If the amount of CO2 produced is 44 gms, then How many Kgs of Glucose was in the feed?

a) 30

b) 60

c) 90

d) 120

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9. By taking 360 gms of Glucose how many gms of CO2 can be produced?

a) 228

b) 328

c) 428

d) 528

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10. By taking 64 gms of O2, How many gms of H2O can be produced?

a) 18

b) 36

c) 54

d) 72